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Solution :

Let `A_1` and `A_2` are area of the shaded and unshaded regions respectively.<br>
Let side of the square is `a` cm.<br>
Then,<br>
`A_1+A_2 = a^2->(1)`...[Area of square `= a^2` ]<br>
`Also, A_1/4+A_2/2 = pi/2(a/2)^2 = (pia^2)/8`<br>
`=>A_1+2A_2 = (pia^2)/2->(2)`<br>
From (1), <br>
`=>A_1+2(a^2-A_1) = (pia^2)/2`<br>
`=>A_1 = 2a^2-(pia^2)/2`<br>
`=>A_1 = a^2(2-pi/2)`<br>
`=>A_1 = (14)^2(2-22/(2*7))` ... [As `a = 14`] <br>
`A_1 = 196(3/7) = 84cm^2`<br>
So, required area is `84 cm^2`.<br>**What we already learned in previous classes**

**Perimeter and Area of a circle**

**Area enclosed by two concentric circles**

**Some Useful Results**

**Minor and major sector**

**Area of a sector**

**Find the area of a sector whose radius is 14 cm and angle of sector is `45^@`.**

**Some important points related to clock**

**Major and Minor segment**

**Area of a segment**